Advertisements
Advertisements
प्रश्न
D, E and F are the mid-points of the sides BC, CA and AB, respectively of an equilateral triangle ABC. Show that ∆DEF is also an equilateral triangle.
Advertisements
उत्तर
Given in the question, D, E and F are the mid-points of the sides BC, CA and AB, respectively of an equivalent ∆ABC.
To proof that ∆DEF is an equilateral triangle.

Proof: In ∆ABC, E and F are the mid-points of AC and AB respectively, then EF || BC.
So, EF = `1/2` BC ...(I)
DF || AC, DE || AB
DE = `1/2` AB and FD = `1/2` AC [By mid-point theorem] ...(II)
Now, ∆ABC is an equilateral triangle
AB = BC = CA
`1/2` AB = `1/2` BC = `1/2` CA ...[Dividing by 2 in the above equation]
So, DE = EF = FD ...[From equation (I) and (II)]
Since, all sides of ADEF are equal.
Hence, ∆DEF is an equilateral triangle
Hence proved.
APPEARS IN
संबंधित प्रश्न
In below Fig, ABCD is a parallelogram in which P is the mid-point of DC and Q is a point on AC such that CQ = `1/4` AC. If PQ produced meets BC at R, prove that R is a mid-point of BC.

The diagonals of a quadrilateral intersect at right angles. Prove that the figure obtained by joining the mid-points of the adjacent sides of the quadrilateral is rectangle.
In the given figure, AD and CE are medians and DF // CE.
Prove that: FB = `1/4` AB.
In triangle ABC; M is mid-point of AB, N is mid-point of AC and D is any point in base BC. Use the intercept Theorem to show that MN bisects AD.
In ΔABC, D is the mid-point of AB and E is the mid-point of BC.
Calculate:
(i) DE, if AC = 8.6 cm
(ii) ∠DEB, if ∠ACB = 72°
In the given figure, ABCD is a trapezium. P and Q are the midpoints of non-parallel side AD and BC respectively. Find: DC, if AB = 20 cm and PQ = 14 cm
Side AC of a ABC is produced to point E so that CE = `(1)/(2)"AC"`. D is the mid-point of BC and ED produced meets AB at F. Lines through D and C are drawn parallel to AB which meets AC at point P and EF at point R respectively. Prove that: 4CR = AB.
In ΔABC, D, E and F are the midpoints of AB, BC and AC.
If AE and DF intersect at G, and M and N are the midpoints of GB and GC respectively, prove that DMNF is a parallelogram.
In the given figure, PS = 3RS. M is the midpoint of QR. If TR || MN || QP, then prove that:
ST = `(1)/(3)"LS"`
E is the mid-point of a median AD of ∆ABC and BE is produced to meet AC at F. Show that AF = `1/3` AC.
