हिंदी

ABCD is a quadrilateral in which P, Q, R and S are mid-points of the sides AB, BC, CD and DA (see the given figure). AC is a diagonal. Show that: i. SR || AC and SR = 12AC ii. PQ = SR - Mathematics

Advertisements
Advertisements

प्रश्न

ABCD is a quadrilateral in which P, Q, R and S are mid-points of the sides AB, BC, CD and DA (see the given figure). AC is a diagonal. Show that:

  1. SR || AC and SR = `1/2AC`
  2. PQ = SR
  3. PQRS is a parallelogram.

योग
Advertisements

उत्तर

(i) In ΔADC, S and R are the mid-points of sides AD and CD respectively.

In a triangle, the line segment joining the mid-points of any two sides of the triangle is parallel to the third side and is half of it.

∴ SR || AC and SR = `1/2AC`      ...(1)

(ii) In ΔABC, P and Q are mid-points of sides AB and BC respectively. Therefore, by using the mid-point theorem,

PQ || AC and PQ = `1/2AC`       ...(2)

Using equations (1) and (2), we obtain

PQ || SR and PQ = SR         ...(3)

⇒ PQ = SR

(iii) From equation (3), we obtained

PQ || SR and PQ = SR

Clearly, one pair of opposite sides of quadrilateral PQRS is parallel and equal.

Hence, PQRS is a parallelogram.

shaalaa.com
  क्या इस प्रश्न या उत्तर में कोई त्रुटि है?
अध्याय 8: Quadrilaterals - EXERCISE 8.2 [पृष्ठ ११३]

APPEARS IN

एनसीईआरटी Mathematics [English] Class 9
अध्याय 8 Quadrilaterals
EXERCISE 8.2 | Q 1. | पृष्ठ ११३

वीडियो ट्यूटोरियलVIEW ALL [1]

संबंधित प्रश्न

In below Fig, ABCD is a parallelogram in which P is the mid-point of DC and Q is a point on AC such that CQ = `1/4` AC. If PQ produced meets BC at R, prove that R is a mid-point of BC.


In Δ ABC, AD is the median and DE is parallel to BA, where E is a point in AC. Prove that BE is also a median.


In the figure, give below, 2AD = AB, P is mid-point of AB, Q is mid-point of DR and PR // BS. Prove that:
(i) AQ // BS
(ii) DS = 3 Rs.


D, E and F are the mid-points of the sides AB, BC and CA of an isosceles ΔABC in which AB = BC. Prove that ΔDEF is also isosceles.


If L and M are the mid-points of AB, and DC respectively of parallelogram ABCD. Prove that segment DL and BM trisect diagonal AC.


ABCD is a parallelogram.E is the mid-point of CD and P is a point on AC such that PC = `(1)/(4)"AC"`. EP produced meets BC at F. Prove that: F is the mid-point of BC.


ABCD is a kite in which BC = CD, AB = AD. E, F and G are the mid-points of CD, BC and AB respectively. Prove that: The line drawn through G and parallel to FE and bisects DA.


In a parallelogram ABCD, E and F are the midpoints of the sides AB and CD respectively. The line segments AF and BF meet the line segments DE and CE at points G and H respectively Prove that: ΔHEB ≅ ΔHFC


In AABC, D and E are two points on the side AB such that AD = DE = EB. Through D and E, lines are drawn parallel to BC which meet the side AC at points F and G respectively. Through F and G, lines are drawn parallel to AB which meet the side BC at points M and N respectively. Prove that BM = MN = NC.


The figure obtained by joining the mid-points of the sides of a rhombus, taken in order, is ______.


Share
Notifications

Englishहिंदीमराठी


      Forgot password?
Use app×