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(English Medium) ICSE Class 9 - CISCE Question Bank Solutions for Mathematics

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Mathematics
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If p = log 20 and q = log 25 , find the value of x , if 2log( x + 1 ) = 2p - q. 

[8] Logarithms
Chapter: [8] Logarithms
Concept: undefined >> undefined

If log2(x + y) = log3(x - y) = `log 25/log 0.2`, find the values of x and y.

[8] Logarithms
Chapter: [8] Logarithms
Concept: undefined >> undefined

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Given : `log x/ log y = 3/2` and log (xy) = 5; find the value of x and y.

[8] Logarithms
Chapter: [8] Logarithms
Concept: undefined >> undefined

Given log10x = 2a and log10= `b/2`. Write 10a in terms of x.

[8] Logarithms
Chapter: [8] Logarithms
Concept: undefined >> undefined

Given log10x = 2a and log10= `b/2`. Write 102b + 1 in terms of y.

[8] Logarithms
Chapter: [8] Logarithms
Concept: undefined >> undefined

Evaluate: loga × logc b × loga c.

[8] Logarithms
Chapter: [8] Logarithms
Concept: undefined >> undefined

Given log10x = 2a and log10= `b/2. "If"  log_10^p = 3a - 2b`, express P in terms of x and y.

[8] Logarithms
Chapter: [8] Logarithms
Concept: undefined >> undefined

Solve : log5( x + 1 ) - 1 = 1 + log5( x - 1 ).

[8] Logarithms
Chapter: [8] Logarithms
Concept: undefined >> undefined

Solve for x, if : logx49 - logx7 + log`1/343` + 2 = 0

[8] Logarithms
Chapter: [8] Logarithms
Concept: undefined >> undefined

Evaluate :  log38 ÷ log916 

[8] Logarithms
Chapter: [8] Logarithms
Concept: undefined >> undefined

If a2 = log x , b3 = log y and `a^2/2 - b^3/3` = log c , find c in terms of x and y.

[8] Logarithms
Chapter: [8] Logarithms
Concept: undefined >> undefined

Given x = log1012 , y = log4 2 x log109 and z = log100.4 , find :
(i) x - y - z
(ii) 13x - y - z

[8] Logarithms
Chapter: [8] Logarithms
Concept: undefined >> undefined

Solve for x, `log_x^(15√5) = 2 - log_x^(3√5)`.

[8] Logarithms
Chapter: [8] Logarithms
Concept: undefined >> undefined

Evaluate :  `( log _5^8 )/(( log_25 16 ) xx  ( log_100  10))`

[8] Logarithms
Chapter: [8] Logarithms
Concept: undefined >> undefined

In a quadrilateral ABCD, AB = AD and CB = CD.

Prove that:

  1. AC bisects angle BAD.
  2. AC is the perpendicular bisector of BD.
[14] Rectilinear Figures [Quadrilaterals: Parallelogram, Rectangle, Rhombus, Square and Trapezium]
Chapter: [14] Rectilinear Figures [Quadrilaterals: Parallelogram, Rectangle, Rhombus, Square and Trapezium]
Concept: undefined >> undefined

Prove that the bisectors of the interior angles of a rectangle form a square.

[14] Rectilinear Figures [Quadrilaterals: Parallelogram, Rectangle, Rhombus, Square and Trapezium]
Chapter: [14] Rectilinear Figures [Quadrilaterals: Parallelogram, Rectangle, Rhombus, Square and Trapezium]
Concept: undefined >> undefined

ABCD is a square. A is joined to a point P on BC and D is joined to a point Q on AB. If AP = DQ;

prove that AP and DQ are perpendicular to each other.

[14] Rectilinear Figures [Quadrilaterals: Parallelogram, Rectangle, Rhombus, Square and Trapezium]
Chapter: [14] Rectilinear Figures [Quadrilaterals: Parallelogram, Rectangle, Rhombus, Square and Trapezium]
Concept: undefined >> undefined

Evaluate: `(log_5 8)/(log_25 16 xx Log_100 10)` 

[8] Logarithms
Chapter: [8] Logarithms
Concept: undefined >> undefined

Solve the following:
log (3 - x) - log (x - 3) = 1

[8] Logarithms
Chapter: [8] Logarithms
Concept: undefined >> undefined

Solve the following:
log(x2 + 36) - 2log x = 1

[8] Logarithms
Chapter: [8] Logarithms
Concept: undefined >> undefined
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