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Find the value of a and b in the following:

`(sqrt(2) + sqrt(3))/(3sqrt(2) - 2sqrt(3)) = 2 - bsqrt(6)`

[1] Number Systems
Chapter: [1] Number Systems
Concept: undefined >> undefined

Find the value of a and b in the following:

`(7 + sqrt(5))/(7 - sqrt(5)) - (7 - sqrt(5))/(7 + sqrt(5)) = a + 7/11 sqrt(5)b`

[1] Number Systems
Chapter: [1] Number Systems
Concept: undefined >> undefined

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Rationalise the denominator in the following and hence evaluate by taking `sqrt(2) = 1.414, sqrt(3) = 1.732` and `sqrt(5) = 2.236`, upto three places of decimal.

`4/sqrt(3)`

[1] Number Systems
Chapter: [1] Number Systems
Concept: undefined >> undefined

Rationalise the denominator in the following and hence evaluate by taking `sqrt(2) = 1.414, sqrt(3) = 1.732` and `sqrt(5) = 2.236`, upto three places of decimal.

`6/sqrt(6)`

[1] Number Systems
Chapter: [1] Number Systems
Concept: undefined >> undefined

Rationalise the denominator in the following and hence evaluate by taking `sqrt(2) = 1.414, sqrt(3) = 1.732` and `sqrt(5) = 2.236`, upto three places of decimal.

`(sqrt(10) - sqrt(5))/2`

[1] Number Systems
Chapter: [1] Number Systems
Concept: undefined >> undefined

Rationalise the denominator in the following and hence evaluate by taking `sqrt(2) = 1.414, sqrt(3) = 1.732` and `sqrt(5) = 2.236`, upto three places of decimal.

`sqrt(2)/(2 + sqrt(2)`

[1] Number Systems
Chapter: [1] Number Systems
Concept: undefined >> undefined

Rationalise the denominator in the following and hence evaluate by taking `sqrt(2) = 1.414, sqrt(3) = 1.732` and `sqrt(5) = 2.236`, upto three places of decimal.

`1/(sqrt(3) + sqrt(2))`

[1] Number Systems
Chapter: [1] Number Systems
Concept: undefined >> undefined

Simplify:

`(1/27)^((-2)/3)`

[1] Number Systems
Chapter: [1] Number Systems
Concept: undefined >> undefined

Simplify:

`[((625)^(-1/2))^((-1)/4)]^2`

[1] Number Systems
Chapter: [1] Number Systems
Concept: undefined >> undefined

Simplify:

`64^(-1/3)[64^(1/3) - 64^(2/3)]`

[1] Number Systems
Chapter: [1] Number Systems
Concept: undefined >> undefined

Simplify:

`(8^(1/3) xx 16^(1/3))/(32^(-1/3))`

[1] Number Systems
Chapter: [1] Number Systems
Concept: undefined >> undefined

Simplify:

`(7sqrt(3))/(sqrt(10) + sqrt(3)) - (2sqrt(5))/(sqrt(6) + sqrt(5)) - (3sqrt(2))/(sqrt(15) + 3sqrt(2))`

[1] Number Systems
Chapter: [1] Number Systems
Concept: undefined >> undefined

If `sqrt(2) = 1.414, sqrt(3) = 1.732`, then find the value of `4/(3sqrt(3) - 2sqrt(2)) + 3/(3sqrt(3) + 2sqrt(2))`.

[1] Number Systems
Chapter: [1] Number Systems
Concept: undefined >> undefined

If `a = (3 + sqrt(5))/2`, then find the value of `a^2 + 1/a^2`.

[1] Number Systems
Chapter: [1] Number Systems
Concept: undefined >> undefined

If `x = (sqrt(3) + sqrt(2))/(sqrt(3) - sqrt(2))` and `y = (sqrt(3) - sqrt(2))/(sqrt(3) + sqrt(2))`, then find the value of x2 + y2.

[1] Number Systems
Chapter: [1] Number Systems
Concept: undefined >> undefined

Simplify:

`(256)^(-(4^((-3)/2))`

[1] Number Systems
Chapter: [1] Number Systems
Concept: undefined >> undefined

Find the value of `4/((216)^(-2/3)) + 1/((256)^(- 3/4)) + 2/((243)^(- 1/5))`

[1] Number Systems
Chapter: [1] Number Systems
Concept: undefined >> undefined

If x + 2a is a factor of x5 – 4a2x3 + 2x + 2a + 3, find a.

[2] Introduction to Polynomials
Chapter: [2] Introduction to Polynomials
Concept: undefined >> undefined

Factorise:

2x3 – 3x2 – 17x + 30

[2] Introduction to Polynomials
Chapter: [2] Introduction to Polynomials
Concept: undefined >> undefined

Factorise:

x3 – 6x2 + 11x – 6

[2] Introduction to Polynomials
Chapter: [2] Introduction to Polynomials
Concept: undefined >> undefined
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