Advertisements
Advertisements
प्रश्न
Rationalise the denominator in the following and hence evaluate by taking `sqrt(2) = 1.414, sqrt(3) = 1.732` and `sqrt(5) = 2.236`, upto three places of decimal.
`1/(sqrt(3) + sqrt(2))`
Advertisements
उत्तर
Let `E = 1/(sqrt(3) + sqrt(2))`
For rationalising the denominator multiplying numerator and denominator by `sqrt(3) - sqrt(2)`, we get
= `1/(sqrt(3) + sqrt(2)) xx (sqrt(3) - sqrt(2))/(sqrt(3) - sqrt(2))`
= `(sqrt(3) - sqrt(2))/((sqrt(3))^2 - (sqrt(2)^2)`
= `(sqrt(3) - sqrt(2))/(3 - 2)`
= `sqrt(3) - sqrt(2)` ...`["Put" sqrt(3) = 1.732 "and" sqrt(2) = 1.414]`
= 1.732 – 1.414
= 0.318
APPEARS IN
संबंधित प्रश्न
Recall, π is defined as the ratio of the circumference (say c) of a circle to its diameter (say d). That is, π = `c/d`. This seems to contradict the fact that π is irrational. How will you resolve this contradiction?
Simplify of the following:
`root(3)4 xx root(3)16`
In the following determine rational numbers a and b:
`(3 + sqrt2)/(3 - sqrt2) = a + bsqrt2`
Write the rationalisation factor of \[7 - 3\sqrt{5}\].
If \[x = 2 + \sqrt{3}\] , find the value of \[x + \frac{1}{x}\].
Simplify \[\sqrt{3 + 2\sqrt{2}}\].
\[\sqrt[5]{6} \times \sqrt[5]{6}\] is equal to
After rationalising the denominator of `7/(3sqrt(3) - 2sqrt(2))`, we get the denominator as ______.
Rationalise the denominator of the following:
`sqrt(40)/sqrt(3)`
Rationalise the denominator of the following:
`(sqrt(3) + sqrt(2))/(sqrt(3) - sqrt(2))`
