HSC Science (Computer Science) १२ वीं कक्षा - Maharashtra State Board Important Questions

The pH of 0.001 M HCl solution is ______.

Calculate the pH of buffer solution composed of 0.01 M weak base BOH and 0.02 M of its salt BA. [K_b = 1.8 × 10^–5 for weak base]

Name one amphoteric solvent.

The pH of a weak monoacidic base is 11.2, and its OH^– ion concentration is ______.

Define Acidic buffer solution.

A weak monobasic acid is 10% dissociated in 0.05 M solution. What is the percent dissociation in 0.15 M solution?

Define conjugate acid-base pair.

Write any four applications of buffer solution.

Vinegar contains ______ acid.

Explain buffer action of sodium acetate-acetic acid buffer.

Define acids according to Bronsted-Lowry theory.

Define “Molar conductivity”.

On calculating the strength of current in amperes if a charge of 840C (coulomb) passes through an electrolyte in 7 minutes, it will be

• 1
• 2
• 3
• 4

The charge of how many coulomb is required to deposit 1.0 g of sodium metal (molar mass 23.0 g mol^-1) from sodium ions is -

1. 2098
2. 96500
3. 193000
4. 4196

Draw neat and labelled diagram of dry cell.

Write one statement of first law of thermodyamics and its mathematical expression.

96500 coulombs correspond to the charge on how many electrons?

Resistance of conductivity cell filled with 0.1 M KCl solution is 100 ohms. If the resistance of the same cell when filled with 0.02 M KCl solution is 520 ohms, calculate the conductivity and molar conductivity of 0.02 M KCl solution. [Given: Conductivity of 0.1 M KCl solution is 1.29 S m^-1 .]

The molar conductivity of cation and anion of salt BA are 180 and 220 mhos respectively. The molar conductivity of salt BA at infinite dilution is_____________ .

(a) 90 mhos.cm²                                                                             

(b) 110 mhos.cm².mol^-1

(c) 200 mhos.cm².mol^-1                                                                 

(d) 400 mhos.cm².mol^-1

What is the value of for the following reaction at 298 K -

6CO₂+ 6H₂0_(l) → C6H₁₂0_6(s) ⁺ 60_2(g),

Given that: ΔG° = 2879 kj mol^-1, AS = -210 JK^-1 mol^-1.