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प्रश्न
You are provided with three resistors of resistance 1.0 Ω, 2.0 Ω and 3.0 Ω How would you connect them to obtain the total effective resistance 1.5 Ω? Draw diagram of the arrangement and check it by calculations.
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उत्तर
Two resistors of resistance 1.0 Ω and 2.0 Ω are connected in series and then this combination is connected in parallel with the resistor of resistance 3.0 Ω. The arrangement is shown in given figure alongside
Total resistance of series combination R = 1 + 2 = 3 Ω.
Total effective resistance of parallel combination
R = `(3 xx 3)/(3 + 3) = 1.5 Ω`
संबंधित प्रश्न
Find the expression for resistors connected in series.
Why is the series arrangement not used for domestic circuits?
(i) Two sets A and B, of three bulbs each, are glowing in two separate rooms. When one of the bulbs in set A is fused, the other two bulbs also cease to glow. But in set B, when one bulb fuses, the other two bulbs continue to glow. Explain why this phenomenon occurs.
(ii) Why do we prefer arrangements of Set B for house circuiting?
Give one example to show how the resistance depends on the nature of material of the conductor.
The diagram below shows part of a circuit:
If this arrangement of three resistors was to be replaced by a single resistor, its resistance should be:
(a) 9 Ω
(b) 4 Ω
(c) 6 Ω
(d) 18 Ω
Name the material of wire used for making standard resistances. Give a reason.
If R1 and R2 be the resistance of the filament of 40 W and 60 W respectively operating 220 V, then:
If the current I through a resistor is increased by 100% (assume that temperature remains unchanged), the increase in power dissipated will be:
When a 4 Ω resistor is connected across the terminals of a 2 V battery, the number of coulombs passing through the resistor per second is:
