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प्रश्न
In the circuit shown below, calculate the equivalent resistance between the points (i) A and B, (ii) C and D.
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उत्तर
(i) Between the points A and B : Three resistance 2 Ω, 2Ω, 2Ω are in series.
The equivalent resistance R' = 2 + 2 + 2 = 6 Ω
This is joined in parallel with a resistance 2Ω
The equivalent resistance R = `(2 xx 6)/(2 + 6) = 12/8 = 15. Omega`
(ii) Between the points C and D:
The above combination of equivalent resistance 1.5 Ω is in series with two resistances 2Ω and 2Ω
Total effective resistance between the points C and D is R
= 1.5 + 2 + 2 = 5.5
संबंधित प्रश्न
(i) Two sets A and B, of three bulbs each, are glowing in two separate rooms. When one of the bulbs in set A is fused, the other two bulbs also cease to glow. But in set B, when one bulb fuses, the other two bulbs continue to glow. Explain why this phenomenon occurs.
(ii) Why do we prefer arrangements of Set B for house circuiting?
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