हिंदी

∫x3tan-1x dx

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प्रश्न

`int x^3tan^(-1)x  "d"x`

योग
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उत्तर

Let I = `int x^3*tan^(-1)x*"d"x`

= `int (tan^-1x)x^3  "d"x`

= `(tan^-1x) int  x^3  "d"x - int["d"/("d"x) (tan^-1x) int x^3  "d"x]  "d"x`

= `(tan^-1x)*(x^4/4) - int 1/(1 + x^2)* x^4/4  "d"x`

= `x^4/4 tan^-1x + 1/4 int ((-x^4))/(1 + x^2) * "d"x`

= `x^4/4 tan^-1x + 1/4 int ((1 - x^4) - 1)/(1 + x)  "d"x`

= `x^4/4 tan^-1x + 1/4 int ((1 - x^2)(1 + x^2) - 1)/(1 + x^2)  "d"x`

= `x^4/4 tan^-1x + 1/4 int (1 - x^2 - 1/(1 + x^2))  "d"x`

= `x^4/4 tan^-1x + 1/4 (x - x^3/3 - tan^-1x) + "c"`

∴ I = `1/4 tan^-1x (x^4 - 1) - x/12 (x^2 - 3) + "c"`

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अध्याय 2.3: Indefinite Integration - Long Answers III

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