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Find : ∫ Sin ( X − a ) Sin ( X + a ) D X

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प्रश्न

Find : 

`∫ sin(x-a)/sin(x+a)dx`

योग
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उत्तर

`∫ sin(x-a)/sin(x+a)dx`

`I = ∫ sin(x-a)/sin(x+a)dx`

= `∫sin(x-a+a-a)/sin(x+a)dx`

= `∫sin(x+a-2a)/sin(x+a)dx`

= `∫(sin(x+a) cos2a - sin 2acos(x+a))/sin(x+a)dx`

= `∫ cos 2a  dx - ∫ sin 2acot(x+a)dx` 

`I = x cos 2a - sin 2a log |sin(x+a)|+C`

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2018-2019 (March) 65/3/3

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