हिंदी

Integrate the rational function: 5x(x+1)(x2-4)

Advertisements
Advertisements

प्रश्न

Integrate the rational function:

`(5x)/((x + 1)(x^2 - 4))`

योग
Advertisements

उत्तर

`(5x)/((x + 1)(x^2 - 4))`

`= 5/((x + 1)(x + 2)(x - 2))`

`(5x)/((x + 1)(x^2 - 4)) => A/(x + 1) + B/(x + 2) + C/(x - 2)`

⇒ 5x = A(x2 - 4) + B (x + 1)(x - 2) + C(x + 1)(x + 2)

Put x = -1

-5 = -3A + 0 = 0

⇒ A `= 5/3`

Put x = -2

-10 = 0 + B(-1)(-4) + 0

⇒ B `= (-5)/2`

Put x = 2

10 = 0 + 0 + 12C

⇒ C `= 5/6`

`therefore int (5x)/((x + 1)(x^2 - 4)`

`= 5/3 int 1/(x + 1)  dx - 5/2 int 1/(x + 1)  dx + 5/6 int 1/(x - 2)  dx`

`= 5/3  log abs (x + 1) - 5/2  log abs (x + 1) + 5/6  log abs (x - 2) + C`

shaalaa.com
  क्या इस प्रश्न या उत्तर में कोई त्रुटि है?
अध्याय 7: Integrals - Exercise 7.5 [पृष्ठ ३२२]

APPEARS IN

एनसीईआरटी Mathematics Part 1 and 2 [English] Class 12
अध्याय 7 Integrals
Exercise 7.5 | Q 11 | पृष्ठ ३२२

संबंधित प्रश्न

Find: `I=intdx/(sinx+sin2x)`


Integrate the rational function:

`x/((x + 1)(x+ 2))`


Integrate the rational function:

`1/(x^2 - 9)`


Integrate the rational function:

`(1 - x^2)/(x(1-2x))`


Integrate the rational function:

`x/((x -1)^2 (x+ 2))`


Integrate the rational function:

`(2x - 3)/((x^2 -1)(2x + 3))`


Integrate the rational function:

`1/(x(x^n + 1))` [Hint: multiply numerator and denominator by xn − 1 and put xn = t]


Integrate the rational function:

`(cos x)/((1-sinx)(2 - sin x))` [Hint: Put sin x = t]


Integrate the rational function:

`((x^2 +1)(x^2 + 2))/((x^2 + 3)(x^2+ 4))`


Find `int(e^x dx)/((e^x - 1)^2 (e^x + 2))`


Integrate the following w.r.t. x : `(12x + 3)/(6x^2 + 13x - 63)`


Integrate the following w.r.t. x : `(2x)/(4 - 3x - x^2)`


Integrate the following w.r.t. x : `(x^2 + x - 1)/(x^2 + x - 6)`


Integrate the following w.r.t. x : `2^x/(4^x - 3 * 2^x - 4`


Integrate the following w.r.t. x : `(1)/(x(1 + 4x^3 + 3x^6)`


Integrate the following w.r.t. x: `(1)/(sinx + sin2x)`


Integrate the following w.r.t.x : `x^2/sqrt(1 - x^6)`


Integrate the following w.r.t.x : `(1)/(2cosx + 3sinx)`


Integrate the following w.r.t.x:

`x^2/((x - 1)(3x - 1)(3x - 2)`


Integrate the following w.r.t.x : `sqrt(tanx)/(sinx*cosx)`


Evaluate: `int (2"x" + 1)/(("x + 1")("x - 2"))` dx


Evaluate:

`int x/((x - 1)^2(x + 2)) dx`


Evaluate: `int ("3x" - 1)/("2x"^2 - "x" - 1)` dx


Evaluate: `int (2"x"^3 - 3"x"^2 - 9"x" + 1)/("2x"^2 - "x" - 10)` dx


`int sqrt(4^x(4^x + 4))  "d"x`


`int 1/(4x^2 - 20x + 17)  "d"x`


`int (sinx)/(sin3x)  "d"x`


`int sec^3x  "d"x`


`int (x^2 + x -1)/(x^2 + x - 6)  "d"x`


`int xcos^3x  "d"x`


Choose the correct alternative:

`int sqrt(1 + x)  "d"x` =


Verify the following using the concept of integration as an antiderivative

`int (x^3"d"x)/(x + 1) = x - x^2/2 + x^3/3 - log|x + 1| + "C"`


Evaluate the following:

`int (x^2 "d"x)/((x^2 + "a"^2)(x^2 + "b"^2))`


Find: `int x^4/((x - 1)(x^2 + 1))dx`.


Find : `int (2x^2 + 3)/(x^2(x^2 + 9))dx; x ≠ 0`.


If \[\int\frac{2x+3}{(x-1)(x^{2}+1)}\mathrm{d}x\] = \[=\log_{e}\left\{(x-1)^{\frac{5}{2}}\left(x^{2}+1\right)^{a}\right\}-\frac{1}{2}\tan^{-1}x+\mathrm{A}\] where A is an arbitrary constant, then the value of a is


Share
Notifications

Englishहिंदीमराठी


      Forgot password?
Use app×