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Integrate the following with respect to the respective variable : cos7x-cos8x1+2cos5x

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प्रश्न

Integrate the following with respect to the respective variable : `(cos 7x - cos8x)/(1 + 2 cos 5x)`

योग
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उत्तर

`int (cos 7x - cos8x)/(1 + 2 cos 5x)*dx`

= `int (sin5x(cos7x - cos8x))/(sin5x(1 + 2 cos5x))*dx`

= `int (sin5x (cos7x - cos8x))/(sin5x + 2 sin 5x cos5x)*dx`

= `int (sin5x(cos7x - cos8x))/(sin5x + sin 10x)*dx`

= `int (2sin(5x/2)*cos ((5x)/2) xx 2sin ((7x + 8x)/2)*sin((8x - 7x)/2))/(2sin ((10x + 5x)/2)*cos  ((10x - 5x)/2))*dx`

= `int (2sin ((5x)/2)*cos((5x)/2) xx 2sin((15x)/2)*sin(x/2))/(2sin((15x)/2)*cos((5x)/2))*dx`

= `int 2sin ((5x)/2)*sin(x/2)*dx`

= `int[cos ((5x)/2 - x/2) - cos((5x)/2 + x/2)]*dx`

= `int (cos 2x - cos 3x)*dx`

= `int cos2x*dx - int cos3*dx`

= `(sin2x)/(2) - (sin3x)/(3) + c`.

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अध्याय 3: Indefinite Integration - Miscellaneous Exercise 3 [पृष्ठ १५०]

APPEARS IN

बालभारती Mathematics and Statistics 2 (Arts and Science) [English] Standard 12 Maharashtra State Board
अध्याय 3 Indefinite Integration
Miscellaneous Exercise 3 | Q 2.8 | पृष्ठ १५०

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