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∫x+sinx1-cosx dx - Mathematics and Statistics

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प्रश्न

`int (x + sinx)/(1 - cosx)  "d"x`

योग
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उत्तर

Let I = `int (x + sinx)/(1 - cosx)  "d"x`

= `int ((x + 2 sin x/2 cos x/2)/(2 sin^2 x/2)) "d"x`

= `int (x/(2sin^2 x/2) + (2sin x/2 cos x/2)/(2sin^2 x/2))  "d"x`

= `1/2 int x "cosec"^2 x/2  "d"x + int  (cos x/2)/(sin x/2)  "d"x`

= `1/2[x int "cosec"^2 x/2  "d"x - int ("d"/("d"x)(x) int "cosec"^2 x/2  "d"x) "d"x] + int cot  x/2  "d"x`

= `1/2[x((-cot  x/2)/(1/2))  - int1 * ((- cot  x/2)/(1/2)) "d"x] + int cot  x/2  "d"x`

= `1/2(-2x cot  x/2 + 2 int cot  x/2  "d"x) + int  cot  x/2  "d"x`

= `- x cot  x/2 + int  cot  x/2  "d"x + int  cot  x/2  "d"x`

= `- x cot  x/2 + 2 int cot  x/2  "d"x`

= `- x cot  x/2 + 2 * (log|sin(x/2)|)/(1/2) + "c"`

= `- x cot  x/2 + 4log |sin(x/2)| + "c"`

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अध्याय 2.3: Indefinite Integration - Long Answers III

वीडियो ट्यूटोरियलVIEW ALL [2]

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