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∫14x2-20x+17 dx - Mathematics and Statistics

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प्रश्न

`int 1/(4x^2 - 20x + 17)  "d"x`

योग
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उत्तर

Let I = `int 1/(4x^2 - 20x + 17)  "d"x`

= `int 1/(4(x^2 - 5x + 17/4))  "d"x`

`(1/2  "coefficient of"  x)^2 = (1/2 xx (-5))^2`

= `25/4`

∴ I = `1/4 int 1/(x^2 - 5x + 25/4 - 25/4 + 17/4)  "d"x`

= `1/4 int 1/((x - 5/2)^2 - 2)  "d"x`

= `1/4 int 1/((x - 5/2)^2 - (sqrt(2))^2)  "d"x`

= `1/4 * 1/(2sqrt(2))  log |(x - 5/2 - sqrt(2))/(x - 5/2 + sqrt(2))| + "c"`

∴ I = `1/(8sqrt(2)) log|(2x - 5 - 2sqrt(2))/(2x - 5 + 2sqrt(2))| + "c"`

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अध्याय 2.3: Indefinite Integration - Short Answers II

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