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`X^2-6x+3=0`

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प्रश्न

`x^2-6x+3=0` 

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उत्तर

`x^2-6x+3=0` 

⇒`x^2-6x=-3` 

⇒`x^2-2xx x xx3+3^2=-3+3^2`             (Adding `3^2` on both sides)

⇒`(x-3)^2=-3+9=6` 

⇒`x-3=+-sqrt6`                         (Taking square root on the both sides) 

⇒`x-3=sqrt6  or  x-3=-sqrt6` 

⇒`x=3+-sqrt6  or  x=3-sqrt6`  

Hence, `3+sqrt6 and 3-sqrt6` are the roots of the given equation. 

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अध्याय 4: Quadratic Equations - Exercises 2

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आर.एस. अग्रवाल Mathematics [English] Class 10
अध्याय 4 Quadratic Equations
Exercises 2 | Q 1

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