Advertisements
Advertisements
प्रश्न
Solve the following equation by factorization
3(y2 – 6) = y(y + 7) – 3
Advertisements
उत्तर
3(y2 – 6) = y(y + 7) – 3
⇒ 3(y2 - 6) = y2 + 7y - 3
⇒ 3y2 - 18 = y2 + 7y - 3
⇒ 3y2 - y2 - 7y - 18 + 3 = 0
⇒ 2y2 - 7y - 15 = 0
⇒ 2y2 - 10y + 3y - 15 = 0
2y(y - 5) + 3(y - 5) = 0
⇒ (y - 5) (2y + 3) = 0
Either y - 5 = 0,
then y = 5
or
2y + 3 = 0,
then 2y = -3
⇒ y = `(-3)/(2)`
Hence y = `(-3)/(2)`, 5.
APPEARS IN
संबंधित प्रश्न
Solve the equation `4/x-3=5/(2x+3); xne0,-3/2` for x .
Solve the following quadratic equations by factorization:
`(x-1/2)^2=4`
Find the value of k for which the following equations have real and equal roots:
\[\left( k + 1 \right) x^2 - 2\left( k - 1 \right)x + 1 = 0\]
Solve the following equation:
(2x+3) (3x-7) = 0
Solve the following equation: 2x2 - x - 6 = 0
Solve the following quadratic equation by factorisation:
x2 + 3x - 18 = 0
Solve the following equation by factorization
3(x – 2)2 = 147
Find the roots of the following quadratic equation by the factorisation method:
`2x^2 + 5/3x - 2 = 0`
A train, travelling at a uniform speed for 360 km, would have taken 48 minutes less to travel the same distance if its speed were 5 km/h more. Find the original speed of the train.
4x2 – 9 = 0 implies x is equal to ______.
