Advertisements
Advertisements
प्रश्न
Solve the following equation by factorization
x2– 4x – 12 = 0,when x∈N
Advertisements
उत्तर
x2 – 4x – 12 = 0
⇒ x2 – 6x + 2x – 12 = 0
⇒ x (x – 6) + 2 (x – 6) = 0
⇒ (x – 6) (x + 2) = 0
Either x – 6 = 0, then x = 6
or x + 2 = 0, then x = -2
But -2 is not a natural number
∴ x = 6.
APPEARS IN
संबंधित प्रश्न
Divide 29 into two parts so that the sum of the squares of the parts is 425.
Without solving the following quadratic equation Find the value of p for which the roots are equal
`px^2 - 4x + 3 = 0`
Solve the following quadratic equations by factorization:
\[\frac{x - 2}{x - 3} + \frac{x - 4}{x - 5} = \frac{10}{3}; x \neq 3, 5\]
Find the value of k for which the following equations have real and equal roots:
\[\left( k + 1 \right) x^2 - 2\left( k - 1 \right)x + 1 = 0\]
Solve the following equation: `1/("x" - 1) + 2/("x" - 1) = 6/"x" , (x ≠ 0)`
Solve equation using factorisation method:
x2 – (a + b)x + ab = 0
Solve the following quadratic equation using factorization method:
`"x"^2-11"x"+24=0`
In each of the following, determine whether the given values are solution of the given equation or not:
`x^2 - sqrt(2) - 4 = 0; x = -sqrt(2), x = -2sqrt(2)`
Solve the following equation by factorization
2x2 – 9x + 10 = 0,when x∈N
Solve the following equation by factorization
`sqrt(3)x^2 + 10x + 7sqrt(3)` = 0
