Question

Find the tow consecutive positive odd integer whose product s 483. 

Answer 1

Let the two consecutive positive odd integers be x and (x  +2).
According to the given condition,  

`x(x+2)=483` 

⇒`x^2+2x-483=0` 

⇒`x^2+23x-21x-483=0` 

⇒`x(x+23)-21(x+21)=0` 

⇒`(x+23) (x+21)=0` 

⇒`x+23=0  or  x-21=0` 

⇒`x=-23  or  x=21` 

∴ x =21  (x is a positive odd integer) 

When `x=21` 

`x+2=21+2=23` 

Hence, the required integers are 21 and 23.