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Find the Tow Consecutive Positive Odd Integer Whose Product S 483. - Mathematics

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प्रश्न

Find the tow consecutive positive odd integer whose product s 483. 

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उत्तर

Let the two consecutive positive odd integers be x and (x  +2).
According to the given condition,  

`x(x+2)=483` 

⇒`x^2+2x-483=0` 

⇒`x^2+23x-21x-483=0` 

⇒`x(x+23)-21(x+21)=0` 

⇒`(x+23) (x+21)=0` 

⇒`x+23=0  or  x-21=0` 

⇒`x=-23  or  x=21` 

∴ x =21  (x is a positive odd integer) 

When `x=21` 

`x+2=21+2=23` 

Hence, the required integers are 21 and 23.

 

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अध्याय 10: Quadratic Equations - Exercises 5

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आर.एस. अग्रवाल Mathematics [English] Class 10
अध्याय 10 Quadratic Equations
Exercises 5 | Q 10

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