Advertisements
Advertisements
प्रश्न
Solve: x(x + 1) (x + 3) (x + 4) = 180.
Advertisements
उत्तर
Given equation
x(x + 1) (x + 3) (x + 4) = 180
⇒ [(x + 0) (x + 4)] [(x + 1) (x + 3)] = 180
⇒ (x2 + 4x) (x2 + 4x + 3) - 180 = 0
Put x2 + 4x = y,
then it becomes y(y + 3) - 180 = 0
⇒ y2 + 3y - 180 = 0
⇒ y2 + 15y - 12y - 180 = 0
⇒ y(y + 15) - 12(y + 15) = 0
⇒ (y + 15) (y - 12) = 0
⇒ y = 15 = 0 or y = 12
But x2 + 4x = y
Then x2 + 4x = -15
x2 + 4x + 15 = 0
or
x2 + 4x = 12
⇒ x2 + 4x - 12 = 0
x2 + ax + 15 = 0 gives x = `(-4 ± sqrt((4)^2 - 4 xx 15))/(2)`
= `(-4 ± sqrt(16 - 60))/(2)`
= `(-4 ± sqrt(-34))/(2)`
∴ Roots of the equation are imaginary hence not acceptable.
or
x2 + 4x - 12 = 0
⇒ x2 + 6x - 2x - 12 = 0
⇒ x (x + 6) -2 (x + 6) = 0
⇒ (x + 6) (x - 2) = 0
⇒ x + 6 = 0 or x - 2 = 0
⇒ x = -6 or x = 2.
संबंधित प्रश्न
Solve for x : 12abx2 – (9a2 – 8b2 ) x – 6ab = 0
Solve the following quadratic equations by factorization:
`3x^2 - 2sqrt6x + 2 = 0`
Solve the following quadratic equations by factorization:
`1/(x + 4) - 1/(x - 7) = 11/30, x ≠ 4, 7`
The product of Shikha’s age five years ago and her age 8 years later is 30, her age at both times being given in years. Find her present age.
A girls is twice as old as her sister. Four years hence, the product of their ages (in years) will be 160. Find their present ages.
If −5 is a root of the quadratic equation\[2 x^2 + px - 15 = 0\] and the quadratic equation \[p( x^2 + x) + k = 0\] has equal roots, find the value of k.
The sum of the ages of a father and his son is 45 years. Five years ago, the product of their ages was 124. Determine their present ages.
If an integer is added to its square the sum is 90. Find the integer with the help of a quadratic equation.
The hotel bill for a number of people for an overnight stay is Rs. 4800. If there were 4 more, the bill each person had to pay would have reduced by Rs. 200. Find the number of people staying overnight.
Find the roots of the following quadratic equation by the factorisation method:
`3sqrt(2)x^2 - 5x - sqrt(2) = 0`
