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Find Two Consecutive Multiples of 3 Whose Product is 648.

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प्रश्न

Find two consecutive multiples of 3 whose product is 648.

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उत्तर

Le the required consecutive multiples of 3 be 3x and`3(x+1)` 

According to the given condition, 

`3x xx3(x+1)=648` 

⇒`9(x^2+x)=648` 

⇒` x^2+x=72` 

⇒`x^2+x-72=0` 

⇒`x^2+x-72=0` 

⇒`x^2+9x-8x-72=0` 

⇒`x(x+9)-8(x+9)=0` 

⇒`(x+9)(x-8)=0` 

⇒`x+9=0   or  x-8=0` 

⇒` x=-9  or  x=8` 

∴` x=8`                  (Neglecting the negative value) 

When `x=8` 

`3x=3xx8=24` 

`3(x+1)=3xx(8+1) =3xx9=27` 

Hence, the required multiples are 24 and 27. 

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अध्याय 4: Quadratic Equations - Exercises 5

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आर.एस. अग्रवाल Mathematics [English] Class 10
अध्याय 4 Quadratic Equations
Exercises 5 | Q 9

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