Question

`x^2-6x+3=0` 

Answer 1

`x^2-6x+3=0` 

⇒`x^2-6x=-3` 

⇒`x^2-2xx x xx3+3^2=-3+3^2`             (Adding `3^2` on both sides)

⇒`(x-3)^2=-3+9=6` 

⇒`x-3=+-sqrt6`                         (Taking square root on the both sides) 

⇒`x-3=sqrt6  or  x-3=-sqrt6` 

⇒`x=3+-sqrt6  or  x=3-sqrt6`  

Hence, `3+sqrt6 and 3-sqrt6` are the roots of the given equation.