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प्रश्न
Solve the following equation :
`sqrt 2 "x"^2 - 3"x" - 2 sqrt 2 = 0`
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उत्तर
`sqrt 2 "x"^2 - 3"x" - 2 sqrt 2 = 0`
`"x"^2 - 3/sqrt 2 "x" - 2 = 0`
`"x"^2 + 1/sqrt 2 "x" - 2 sqrt 2 - 2 = 0`
`"x" ("x" + 1/ sqrt 2) - 2 sqrt 2 ("x" + 1/ sqrt 2) = 0`
`("x" + 1/sqrt 2)("x" - 2 sqrt 2) = 0`
`("x" + 1/sqrt 2) = 0 , ("x" - 2 sqrt 2) = 0`
x = `-1/sqrt 2` , `"x" = 2 sqrt 2`
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