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Write the product formed when alkyl halide reacts with silver nitrite. - Chemistry

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प्रश्न

Write the product formed when alkyl halide reacts with silver nitrite.

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उत्तर

\[\ce{\underset{(Alkyl halide)}{R - X} + \underset{(Silver nitrite)}{Ag NO2} -> \underset{Nitroalkane}{R - NO2 + Ag - X}}\]

Nitroalkane is formed when alkyl halide reacts with silver nitrite.

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Chemical Properties of Halogen Derivatives
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2021-2022 (March) Set 1

संबंधित प्रश्न

from the following pair would undergo SN2 faster from the other?

a. CH3CH2CH2I      b. CH3CH2CH2Cl


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1-Chloropropane to 1-nitropropane


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\[\ce{2-Bromobutane->[Alc.KOH]A->[][Br2]B->[][NaNH2]C}\]


Observe the following and answer the question given below.

Comment on the bond length of C–X bond in it.


The following will react faster by SN1 mechanism


Major product of the following reaction is _______________

\[\ce{CH3-CH2-Mg-Br + NH3 ->?}\]


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The order of reactivities of the following alkyl halides for an SN2 reaction is ______.


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Which among the following statements is not correct about SN2 reaction mechanism?


Complete the following reactions giving a major product.

\[\begin{array}{cc}
\ce{CH3}\phantom{................}\\
|\phantom{..................}\\
\ce{CH3 - C - CH2 - Cl ->[Na/dry ether] A}\\
|\phantom{..................}\\
\ce{CH3}\phantom{................}
\end{array}\]


Observe the following and answer the question given below:

Comment on the bond length of C-X bond in it.


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Complete the following reaction giving major product.

\[\begin{array}{cc}
\ce{CH3}\phantom{...............}\\
|\phantom{..................}\\
\ce{CH3 - C - CH2 - Cl ->[Na/dry ether]A}\\
|\phantom{...................}\\
\ce{CH3}\phantom{.................}
\end{array}\]


Complete the following reaction giving major product.

\[\begin{array}{cc}
\ce{CH3}\phantom{................}\\
|\phantom{..................}\\
\ce{CH3 - C - CH2 - Cl ->[Na/dry ether]A}\\
|\phantom{..................}\\
\ce{CH3}\phantom{................}
\end{array}\]


Give a reason for the following:

Ethoxy ethane with conc. HI at 373 K gives C2H5OH and CH3I but not CH3OH and C2H5I.


Complete the following reaction giving major product.

\[\begin{array}{cc}
\ce{CH3}\phantom{.................}\\
|\phantom{...................}\\
\ce{CH3 - C - CH2 - Cl ->[Na/dry ether] A}\\
|\phantom{...................}\\
\ce{CH3}\phantom{.................}\\
\end{array}\]


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