हिंदी

Write the product formed when alkyl halide reacts with silver nitrite.

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प्रश्न

Write the product formed when alkyl halide reacts with silver nitrite.

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उत्तर

\[\ce{\underset{(Alkyl halide)}{R - X} + \underset{(Silver nitrite)}{Ag NO2} -> \underset{Nitroalkane}{R - NO2 + Ag - X}}\]

Nitroalkane is formed when alkyl halide reacts with silver nitrite.

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2021-2022 (March) Set 1

संबंधित प्रश्न

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\[\begin{array}{cc}\ce{CH3 - CH = CH3 ->[Red P/Br2] A ->[Ag2O/H2O]B}\\|\phantom{.........................}\\
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\[\ce{Isopropyl alcohol ->[\triangle][PBr3] A ->[][NH3 excess] B}\]


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Can it react by SN1 mechanism? Justify your answer.


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\[\begin{array}{cc}
\ce{CH3}\\
|\\
\ce{CH3-C-Cl}\phantom{...}\\
|\\
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\end{array}\]


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\[\ce{2-Bromobutan ->[alc. KOH] A ->[][Br2] B ->[][NANH2] C}\]


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alcoholic sodium hydroxide


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\[\begin{array}{cc}
\ce{CH3}\phantom{................}\\
|\phantom{...................}\\
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|\phantom{...................}\\
\ce{CH3}\phantom{................}
\end{array}\]


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\[\begin{array}{cc}
\ce{CH3}\phantom{................}\\
|\phantom{...................}\\
\ce{CH3 - C - CH2 - Cl->[Na/ dry ether]A}\\
|\phantom{...................}\\
\ce{CH3}\phantom{................}\\
\end{array}\]


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