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प्रश्न
Which of the 3d series of the transition metals exhibits the largest number of oxidation states and why?
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उत्तर
Mn (Z = 25) = 3d5 4s2
Mn has the maximum number of unpaired electrons present in the d-subshell (5 electrons). Hence, Mn exhibits the largest number of oxidation states, ranging from +2 to +7.
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संबंधित प्रश्न
The elements of 3d transition series are given as: Sc Ti V Cr Mn Fe Co
Answer the following: Which element shows only +3 oxidation state?
|
`E_((M^(2+)/M)` |
Cr | Mn | Fe | Co | Ni | Cu |
| -0.91 | -1.18 | -0.44 | -0.28 | -0.25 | -0.34 |
From the given data of E0 values, answer the following questions :
(1) Why is `E_(((Cu^(2+))/(Cu)))` value exceptionally positive
(2) Why is `E_(((Mn^(2+))/(Mn)))` value is highly negative as compared to other elements
(3) Which is the stronger reducing agents Cr2+ or Fe2+ ? Give Reason.
How would you account for the following:
Cobalt (II) is stable in aqueous solutions, but in the presence of complexing reagents, it is easily oxidised.
Comment on the statement that elements of the first transition series possess many properties different from those of heavier transition elements.
NF3 is possible, but NF5 is not. Why?
Following are the transition metal ions of 3d series:
Ti4+, V2+, Mn3+, Cr3+
(Atomic numbers: Ti = 22, V = 23, Mn = 25, Cr = 24)
Answer the following:
1) Which ion is most stable in an aqueous solution and why?
2) Which ion is a strong oxidising agent and why?
3) Which ion is colourless and why?
Dissociation of H2S is suppressed in acidic medium.
Account for the following :
Ti4+ is colourless whereas V4+ is coloured in an aqueous solutions.
Give reason for the following:
The transition metals generally form coloured compounds.
Although fluorine is more electronegative than oxygen, but the ability of oxygen to stabilise higher oxidation states exceeds that of fluorine. Why?
The halides of transition elements become more covalent with increasing oxidation state of the metal. Why?
When a chromite ore (A) is fused with sodium carbonate in free excess of air and the product is dissolved in water, a yellow solution of compound (B) is obtained. After treatment of this yellow solution with sulphuric acid, compound (C) can be crystallised from the solution. When compound (C) is treated with KCl, orange crystals of compound (D) crystallise out. Identify A to D and also explain the reactions.
Why are fluorides of transition metals more stable in their higher oxidation state as compared to the lower oxidation state?
On strong heating AgNO3, the gases evolved are:-
Which does not belong to first transition series?
Which of the following ions has the maximum magnetic moment?
Account for the following:
Transition metals form alloys.
How is the variability in oxidation states of transition metals different from that of p-block elements?
The disproportionation of \[\ce{MnO^{2-}_4}\] in acidic medium resulted in the formation of two manganese compounds A and B. If the oxidation state of Mn in B is smaller than that of A, then the spin-only magnetic moment (µ) value of B in BM is ______. (Nearest integer)
Write the number of unpaired electrons in Cr3+.
(Atomic number of Cr = 24)
