हिंदी
कर्नाटक बोर्ड पी.यू.सी.पीयूसी विज्ञान 2nd PUC Class 12

While filling up of electrons in the atomic orbitals, the 4s orbital is filled before the 3d orbital but reverse happens during the ionisation of the atom. Explain why?

Advertisements
Advertisements

प्रश्न

While filling up of electrons in the atomic orbitals, the 4s orbital is filled before the 3d orbital but reverse happens during the ionisation of the atom. Explain why?

टिप्पणी लिखिए
Advertisements

उत्तर

Electrons are filled to the n + l rule. If an orbital has lower n + l value, then the electron will enter that orbital.

For 3d, n + l = 3 + 2 = 5

4s, n + l = 4 + 0 = 4

So, the electron will first enter 4s and then 3d while filling. But, 4s electrons are held loose by the nucleus and are outside of 3d, so removing a 4s electron becomes easier than removing a 3d electron.

shaalaa.com
  क्या इस प्रश्न या उत्तर में कोई त्रुटि है?
अध्याय 8: The d-and f-Block Elements - Multiple Choice Questions (Type - I) [पृष्ठ १११]

APPEARS IN

एनसीईआरटी एक्झांप्लर Chemistry Exemplar [English] Class 12
अध्याय 8 The d-and f-Block Elements
Multiple Choice Questions (Type - I) | Q 50 | पृष्ठ १११

संबंधित प्रश्न

Why do interstitial compounds have higher melting points than corresponding pure metals?


Account for the following: 

Cr2+ is a strong reducing agent.


`E_((M^(2+)/M)`

Cr Mn Fe Co Ni Cu
-0.91 -1.18 -0.44 -0.28 -0.25 -0.34

From the given data of E0 values, answer the following questions :

(1) Why is `E_(((Cu^(2+))/(Cu)))` value exceptionally positive

(2) Why is `E_(((Mn^(2+))/(Mn)))` value is highly negative as compared to other elements

(3) Which is the stronger reducing agents Cr2+ or Fe2+ ? Give Reason.


What may be the stable oxidation state of the transition element with the following d electron configuration in the ground state of its atom?

3d3


In what way is the electronic configuration of the transition elements different from that of the non-transition elements?


Use Hund’s rule to derive the electronic configuration of Ce3+ ion and calculate its magnetic moment on the basis of ‘spin-only’ formula.


Comment on the statement that elements of the first transition series possess many properties different from those of heavier transition elements.


Transition metals with lowest melting point is ______.


The halides of transition elements become more covalent with increasing oxidation state of the metal. Why?


Assertion (A): Cu cannot liberate hydrogen from acids.

Reason (R): Because it has positive electrode potential.


Assertion: The highest oxidation state of osmium is +8.

Reason: Osmium is a 5d-block element.


Identify the metal and justify your answer.

\[\ce{MO3F}\]


A complex in which dsp2 hybridisation takes place is ______.


Give reason for the following statement:

Physical and chemical properties of the 4d and 5d series of the transition elements are quite similar to expected.


Why Zn, Cd and Hg are not called transition metals?


Consider the following standard electrode potential values:

\[\ce{Fe^{3+}_{ (aq)} + e^- -> Fe^{2+}_{ (aq)}}\], E0 = +0.77 V

\[\ce{MnO^{-4}_{ (aq)} + 8H^+ + 5e^- -> Mn^{2+}_{ (aq)} + 4H2O_{(l)}}\], E0 = +1.51 V

What is the cell potential for the redox reaction?


Write the number of unpaired electrons in Cr3+.
(Atomic number of Cr = 24)


Compare the general characteristics of the first series of the transition metals with those of the second and third series metals in the respective vertical columns. Give special emphasis on the following point:

Oxidation states


Share
Notifications

Englishहिंदीमराठी


      Forgot password?
Use app×