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प्रश्न
When a brown compound of manganese (A) is treated with \[\ce{HCl}\] it gives a gas (B). The gas taken in excess, reacts with \[\ce{NH3}\] to give an explosive compound (C). Identify compounds A, B and C.
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उत्तर
The compounds A, B and C are as follows:
A = \[\ce{MnO2}\], B = \[\ce{Cl2}\], C = \[\ce{NCl3}\]
The reactions are explained as under:
\[\ce{\underset{(A)}{MnO2} + 4HCl -> MnCl2 + \underset{(B)}{Cl2} + 2H2O}\]
\[\ce{\underset{(Excess)}{3Cl2} + NH3 -> \underset{(C)}{NCl3} + 3HCl}\]
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संबंधित प्रश्न
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| Column I (Property) | Column II (Metal) | |
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| (ii) | Element with highest third ionisation enthalpy |
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| (iii) | \[\ce{M}\] in \[\ce{M(CO)6}\] is | (c) \[\ce{Cu}\] |
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\[\ce{MO3F}\]
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