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कर्नाटक बोर्ड पी.यू.सी.पीयूसी विज्ञान 2nd PUC Class 12

In the series Sc (Z = 21) to Zn (Z = 30), the enthalpy of atomization of zinc is the lowest, i.e., 126 kJ mol−1. Why?

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प्रश्न

In the series Sc (Z = 21) to Zn (Z = 30), the enthalpy of atomization of zinc is the lowest, i.e., 126 kJ mol−1. Why?

लघु उत्तरीय
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उत्तर

The electrons of the 3d orbitals of zinc are not used in bonding, whereas the electrons of the d orbitals of all the remaining metals of the 3d series are used in forming bonds. Hence the value of the atomization enthalpy of zinc is the lowest in the series.

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अध्याय 4: The d-block and f-block Elements - Intext Question [पृष्ठ ९५]

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एनसीईआरटी Chemistry Part 1 and 2 [English] Class 12
अध्याय 4 The d-block and f-block Elements
Intext Question | Q 4.2 | पृष्ठ ९५

संबंधित प्रश्न

Account for the following:

Mn shows the highest oxidation state of +7 with oxygen but with fluorine, it shows oxidation state of +4.


`E_((M^(2+)/M)`

Cr Mn Fe Co Ni Cu
-0.91 -1.18 -0.44 -0.28 -0.25 -0.34

From the given data of E0 values, answer the following questions :

(1) Why is `E_(((Cu^(2+))/(Cu)))` value exceptionally positive

(2) Why is `E_(((Mn^(2+))/(Mn)))` value is highly negative as compared to other elements

(3) Which is the stronger reducing agents Cr2+ or Fe2+ ? Give Reason.


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(Atomic nos. : Mn = 25, Cr = 24)


Which one of the following ions is coloured?


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Give reasons for the following:

The transition metals generally form coloured compounds.


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(i) \[\ce{Cr}\]

(ii) \[\ce{Co}\]

(iii) \[\ce{Cu}\]

(iv) \[\ce{Ni}\]


Assertion: Separation of \[\ce{Zr}\] and \[\ce{Hf}\] is difficult.

Reason: Because \[\ce{Zr}\] and \[\ce{Hf}\] lie in the same group of the periodic table.


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Which element of the first transition series has highest third ionisation enthalpy?


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List-I List-II
A. Haber process I. Fe catalyst
B. Wacker oxidation II. PdCl2
C. Wilkinson catalyst III. [(PPh3)3RhCl]
D. Ziegler catalyst IV. TiCl4 with Al(CH3)3

Choose the correct answer from the options given below:


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