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प्रश्न
Silver atom has completely filled d orbitals (4d10) in its ground state. How can you say that it is a transition element?
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उत्तर
Silver (Z = 47) can also show a +2 oxidation state, in which its 4d orbitals are incompletely filled; hence, it is a transition element.
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संबंधित प्रश्न
Explain giving reasons:
Transition metals and many of their compounds show paramagnetic behaviour.
Write down the electronic configuration of Cr3+.
Write down the electronic configuration of Co2+.
Write the different oxidation states of manganese.
Account for the following:
Mn2+ is more stable than Fe2+ towards oxidation to +3 state.
Name the elements of 3d transition series that show maximum number of oxidation states. Why does this happen?
Which transition metal of 3d series has positive E° (M2+/M) value and why?
Out of Cr3+ and Mn3+, which is a stronger oxidising agent and why?
Which among the following is not considered as a part of transition elements?
Electronic configuration of Cu3+ is ____________.
The electronic configuration of \[\ce{Cu(II)}\] is 3d9 whereas that of \[\ce{Cu(I)}\] is 3d10. Which of the following is correct?
Electronic configuration of manganese (Z = 25) is ______
Define transition metals.
Match the properties with the elements of 3d series:
| (i) | lowest enthalpy of atomisation | (p) | Sc |
| (ii) | shows maximum number of oxidation states | (q) | Mn |
| (iii) | transition metal that does not form coloured compounds |
(r) | Zn |
| (s) | Ti |
