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प्रश्न
In what way is the electronic configuration of the transition elements different from that of the non-transition elements?
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उत्तर
The electronic configuration of transition elements is of the type (n – 1)d1–10 ns1–2, and thus they have an incomplete d-orbital, whereas the d-orbital is not found in non-transition elements. Their electronic configuration is of the type ns1–2 or ns2 np1–6.
संबंधित प्रश्न
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| Element | \[\ce{Fe}\] | \[\ce{Co}\] | \[\ce{Ni}\] | \[\ce{Cu}\] |
| Metallic radii/pm | 126 | 125 | 125 | 128 |
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| Column I (Aqueous solution of salt) |
Column II (Colour) |
| (i) \[\ce{FeSO2.7H2O}\] | (a) Green |
| (ii) \[\ce{NiCl2.4H2O}\] | (b) Light pink |
| (iii) \[\ce{MnCl2.4H2O}\] | (c) Blue |
| (iv) \[\ce{CoC12,6H2O}\] | (d) Pale green |
| (v) \[\ce{Cu2 Cl2}\] | (e) Pink |
| (f) Colourless |
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[Ti(H2O)]3+ is coloured while [Sc(H2O)6]3+ is colourless.
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Sc3+ is colourless whereas Ti3+ is coloured in an aqueous solution.
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Reason (R): Greater number of unpaired electrons in transition metals results in weak metallic bonding.
Give a reason for the following:
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