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प्रश्न
In what way is the electronic configuration of the transition elements different from that of the non-transition elements?
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उत्तर
The general electronic configuration of transition elements is (n – 1)d1–10 ns1–2 (or ns0–2), meaning they have an incompletely filled d-subshell in their atomic or common ionic states. In contrast, non-transition elements either lack d-orbitals or have completely filled d-orbitals (d10), and their valence shell configuration is typically ns1−2 or ns1−6.
संबंधित प्रश्न
Complete the following chemical equations:
`(i) Cr_2O_7^(2-)+6Fe^(2+)+14H^+ ->`
`(ii) 2CrO_4^(2-)+2H^+ ->`
`(iii) 2MnO_4^-+5C_2O_4^(2-)+16H^+ ->`
|
`E_((M^(2+)/M)` |
Cr | Mn | Fe | Co | Ni | Cu |
| -0.91 | -1.18 | -0.44 | -0.28 | -0.25 | -0.34 |
From the given data of E0 values, answer the following questions :
(1) Why is `E_(((Cu^(2+))/(Cu)))` value exceptionally positive
(2) Why is `E_(((Mn^(2+))/(Mn)))` value is highly negative as compared to other elements
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(i) \[\ce{Cr}\]
(ii) \[\ce{Co}\]
(iii) \[\ce{Cu}\]
(iv) \[\ce{Ni}\]
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(i) \[\ce{CrO3}\]
(ii) \[\ce{MoO3}\]
(iii) \[\ce{WO3}\]
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Choose the most appropriate answer from the options given below:
