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प्रश्न
A transition element X has an electronic configuration [Ar]4s23d3. Predict its likely oxidation states.
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उत्तर
Electronic configuration of X = [Ar]4s23d3
Vanadium, a transition element, is the one that has been provided. The variable oxidation states + 2, + 3, + 4 and + 5 will be displayed.
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संबंधित प्रश्न
In 3d series (Sc to Zn), which element has the lowest enthalpy of atomisation and why?
How is the variability in oxidation states of transition metals different from that of the non-transition metals? Illustrate with examples.
Following are the transition metal ions of 3d series:
Ti4+, V2+, Mn3+, Cr3+
(Atomic numbers: Ti = 22, V = 23, Mn = 25, Cr = 24)
Answer the following:
1) Which ion is most stable in an aqueous solution and why?
2) Which ion is a strong oxidising agent and why?
3) Which ion is colourless and why?
Although fluorine is more electronegative than oxygen, but the ability of oxygen to stabilise higher oxidation states exceeds that of fluorine. Why?
EΘ of Cu is + 0.34V while that of Zn is – 0.76V. Explain.
On strong heating AgNO3, the gases evolved are:-
Mercury is the only metal liquid at room temperature due to its:-
Account for the following:
Transition metals form alloys.
Which of the following ions acts as a typical transition metal ion?
Account for the following:
Sc3+ is colourless whereas Ti3+ is coloured in an aqueous solution.
