Advertisements
Advertisements
प्रश्न
A transition element X has an electronic configuration [Ar]4s23d3. Predict its likely oxidation states.
Advertisements
उत्तर
Electronic configuration of X = [Ar]4s23d3
Vanadium, a transition element, is the one that has been provided. The variable oxidation states + 2, + 3, + 4 and + 5 will be displayed.
APPEARS IN
संबंधित प्रश्न
Give reasons:
Transition metals show variable oxidation states.
Describe the oxidising action of potassium dichromate and write the ionic equation for its reaction with iodide.
Give reasons for the following:
The transition metals generally form coloured compounds.
EΘ of Cu is + 0.34V while that of Zn is – 0.76V. Explain.
Match the properties given in Column I with the metals given in Column II.
| Column I (Property) | Column II (Metal) | |
| (i) | An element which can show +8 oxidation state | (a) \[\ce{Mn}\] |
| (ii) | 3d block element that can show | (b) \[\ce{Cr}\] |
| upto +7 oxidation state | (c) \[\ce{Os}\] | |
| (iii) | 3d block element with highest melting point | (d) \[\ce{Fe}\] |
It has been observed that first ionization energy of 5 d series of transition elements are higher than that of 3d and 4d series, explain why?
A complex in which dsp2 hybridisation takes place is ______.
Give reason for the following statement:
[Ti(H2O)]3+ is coloured while [Sc(H2O)6]3+ is colourless.
Assertion (A): Transition metals show their highest oxidation state with oxygen.
Reason (R): The ability of oxygen to form multiple bonds to metals.
Describe the oxidising action of potassium dichromate and write the ionic equation for its reaction with H2S.
