Advertisements
Advertisements
प्रश्न
When a 4 Ω resistor is connected across the terminals of a 12 V battery, the number of coulombs passing through the resistor per second is:
(a) 0.3
(b) 3
(c) 4
(d) 12
Advertisements
उत्तर
(b) 3
The number of coulombs passing through the resistor is the current passing through it.
Current = Voltage/Resistance
I = V/R
I = 12/4
I = 3 A
Thus, when a 4 Ω resistor is connected across the terminals of a 12 V battery, the number of coulombs passing through the resistor per second will be 3.
APPEARS IN
संबंधित प्रश्न
In series combination which remains constant?
(a) Voltage
(b) Current
(c) Both current and voltage
(d) Both are variables
Judge the equivalent resistance when the following are connected in parallel − (a) 1 Ω and 106Ω, (b) 1 Ω and 103Ω and 106Ω.
Why is the series arrangement not used for domestic circuits?
How does the resistance of a pure metal change if its temperature decreases?
If five resistances, each of value 0.2 ohm, are connected in series, what will be the resultant resistance?
In series combination of resistances ______.
Name the material of wire used for making standard resistances. Give a reason.
How does the resistivity of a semiconductor depend on temperature?
State expression for Cells connected in parallel.
State a relation between electrical power, resistance and potential difference in an electrical circuit.
Calculate the equivalent resistance between P and Q from the following diagram:
Two resistors of 4Ω and 6Ω are connected in parallel to a cell to draw 0.5 A current from the cell. Calculate the current in each resistor.
With the help of a circuit diagram derive the formula for the resultant resistance of three resistances connected:
- in series and
- in parallel
What is the maximum resistance which can be made using five resistors each of `1/5` W?
Show how you would connect three resistors, each of resistance 6 Ω, so that the combination has a resistance of 4 Ω.
