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Volume versus temperature graphs for a given mass of an ideal gas are shown in figure at two different values of constant pressure. What can be inferred about relation between P1 and P2?

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प्रश्न

Volume versus temperature graphs for a given mass of an ideal gas are shown in figure at two different values of constant pressure. What can be inferred about relation between P1 and P2?

विकल्प

  • P1 > P2

  • P1 = P2

  • P1 < P2

  • data is insufficient.

MCQ
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उत्तर

P1 > P

Explanation:

As we know that the pressure and the quantity of gas in the system are constants. Thus, by using the ideal gas equation 

PV = nRT

V ∝ T .....(When n, P and R are constants)

`V_1/T_1` = constant

Or slope of graph is constant

`V = (nRT)/P`

`(dV)/(dT) = (nR)/P`

Or `(dV)/(dT)` increases when P decreases

Thus, `(dV)/(dT) ∝ 1/P`

This shows that slope P1 is smaller than P2.

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अध्याय 13: Kinetic Theory - Exercises [पृष्ठ ९१]

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एनसीईआरटी एक्झांप्लर Physics Exemplar [English] Class 11
अध्याय 13 Kinetic Theory
Exercises | Q 13.5 | पृष्ठ ९१

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