Advertisements
Advertisements
प्रश्न
0.040 g of He is kept in a closed container initially at 100.0°C. The container is now heated. Neglecting the expansion of the container, calculate the temperature at which the internal energy is increased by 12 J.
Use R = 8.3 J K-1 mol-1
Advertisements
उत्तर
Here ,
m = 0.040g
M = 4g
n = \[\frac{0.040}{4} = 0.01 \]
T1 = (100 + 273) K = 373 K
He is a monoatomic gas. Thus,
\[\ C_v = 3 × (\frac{1}{2}R) \]
⇒ Cv = 1.5 × 8.3 = 12.45
Let the initial internal energy be U1 .
Let the final internal energy be U2 .
U2 -U1 = n Cv ( T2 -T1 )
⇒ 0.01 × 12.45( T2 - 373) = 12
⇒ T2 = 469 K
The temperature in °C can be obtained as follows: 469 - 273 = 196° C
APPEARS IN
संबंधित प्रश्न
A gas is kept in an enclosure. The pressure of the gas is reduced by pumping out some gas. Will the temperature of the gas decrease by Charles's low?
If the molecules were not allowed to collide among themselves, would you expect more evaporation or less evaporation?
Which of the following quantities is the same for all ideal gases at the same temperature?
(a) The kinetic energy of 1 mole
(b) The kinetic energy of 1 g
(c) The number of molecules in 1 mole
(d) The number of molecules in 1 g
Figure shows two vessels A and B with rigid walls containing ideal gases. The pressure, temperature and the volume are pA, TA, V in the vessel A and pB, TB, V in the vessel B. The vessels are now connected through a small tube. Show that the pressure p and the temperature T satisfy `Ρ/T = 1/2 ({P_A}/{T_A}+{P_B}/{T_B))` when equilibrium is achieved.
The temperature and the dew point in an open room are 20°C and 10°C. If the room temperature drops to 15°C, what will be the new dew point?
Answer in brief:
Show that rms velocity of an oxygen molecule is `sqrt2` times that of a sulfur dioxide molecule at S.T.P.
Calculate the average molecular kinetic energy
- per kmol
- per kg
- per molecule
of oxygen at 127°C, given that the molecular weight of oxygen is 32, R is 8.31 J mol−1K−1 and Avogadro’s number NA is 6.02 × 1023 molecules mol−1.
The number of degrees of freedom, for the vibrational motion of a polyatomic molecule, depends on the ______
Above what temperature, all bodies radiate electromagnetic radiation?
The average K.E. of hydrogen molecules at 27° C is E. The average K.E. at 627° C is ____________.
A ring of mass m and radius r rotates about an axis passing through its centre and perpendicular to its plane with angular velocity `omega`. Its kinetic energy is ______.
Average kinetic energy of H2 molecule at 300K is 'E'. At the same temperature, average kinetic energy of O2 molecule will be ______.
A molecule consists of two atoms each of mass 'm' and separated by a distance 'd'. At room temperature the average rotational kinetic energy is 'E', then its angular frequency is ______.
The molecules of a given mass of a gas have root mean square speeds of 100 ms−1 at 27°C and 1.00 atmospheric pressure. What will be the root mean square speeds of the molecules of the gas at 127°C and 2.0 atmospheric pressure?
Two molecules of a gas have speeds of 9 × 10 6 ms−1 and 1 × 106 ms−1, respectively. What is the root mean square speed of these molecules?
For a particle moving in vertical circle, the total energy at different positions along the path ______.
Assuming the expression for the pressure P exerted by an ideal gas, prove that the kinetic energy per unit volume of the gas is `3/2` P.
According to the kinetic theory of gases, at a given temperature, molecules of all gases have the same ______.
At what temperature will therms velocity of a gas be four times its value at STP?
Which of the following materials is diathermanous?
