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1 mole of H2 gas is contained in a box of volume V = 1.00 m3 at T = 300K.

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प्रश्न

1 mole of H2 gas is contained in a box of volume V = 1.00 m3 at T = 300K. The gas is heated to a temperature of T = 3000K and the gas gets converted to a gas of hydrogen atoms. The final pressure would be (considering all gases to be ideal) ______.

विकल्प

  • same as the pressure initially.

  • 2 times the pressure initially.

  • 10 times the pressure initially.

  • 20 times the pressure initially.

MCQ
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उत्तर

1 mole of H2 gas is contained in a box of volume V = 1.00 m3 at T = 300K. The gas is heated to a temperature of T = 3000K and the gas gets converted to a gas of hydrogen atoms. The final pressure would be (considering all gases to be ideal) 20 times the pressure initially.

Explanation:

Consider the diagram, when the molecules break into atoms, the number of moles would become twice.

Now, by ideal gas equation

P = Pressure of gas

N = Number of moles

R = Gas constant

T = Temperature

PV = nRT

As the volume (V) of the container is constant.

As gases break the number of moles becomes twice of initial, so n2 = 2n1

So, P ∝ nT

⇒ `P_2/P_1 = (n_2T_2)/(n_1T_1) = ((2n_1)(3000))/(n_1 (300))` = 20

⇒ P2 = 20P1

Hence, the final pressure of the gas would be 20 times the pressure initially.

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अध्याय 13: Kinetic Theory - Exercises [पृष्ठ ९२]

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एनसीईआरटी एक्झांप्लर Physics Exemplar [English] Class 11
अध्याय 13 Kinetic Theory
Exercises | Q 13.6 | पृष्ठ ९२

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