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Using Binomial Theorem, Write Down the Expansions : (Iv) ( 1 − 3 X ) 7

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प्रश्न

Using binomial theorem, write down the expansions  :

(iv)  \[\left( 1 - 3x \right)^7\]

 

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उत्तर

(iv) (1 − 3x)7

\[=^{7}{}{C}_0 (3x )^0 -^{7}{}{C}_1 (3x )^1 + ^{7}{}{C}_2 (3x )^2 - ^{7}{}{C}_3 (3x )^3 +^{7}{}{C}_4 (3x )^4 - ^{7}{}{C}_5 (3x )^5 +^{7}{}{C}_6 (3x )^6 -^{7}{}{C}_7 (3x )^7 \]

\[ = 1 - 7 \times 3x + 21 \times 9 x^2 - 35 \times 27 x^3 + 35 \times 81 x^4 - 21 \times 243 x^5 + 7 \times 729 x^6 - 2187 x^7 \]

\[ = 1 - 21x + 189 x^2 - 945 x^3 + 2835 x^4 - 5103 x^5 + 5103 x^6 - 2187 x^7\]

 

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Introduction of Binomial Theorem
  क्या इस प्रश्न या उत्तर में कोई त्रुटि है?
अध्याय 18: Binomial Theorem - Exercise 18.1 [पृष्ठ ११]

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आर.डी. शर्मा Mathematics [English] Class 11
अध्याय 18 Binomial Theorem
Exercise 18.1 | Q 1.04 | पृष्ठ ११

संबंधित प्रश्न

Using binomial theorem, write down the expansions  :

(iii)  \[\left( x - \frac{1}{x} \right)^6\]

\[= ^{5}{}{C}_0 (2x )^5 (3y )^0 +^{5}{}{C}_1 (2x )^4 (3y )^1 + ^{5}{}{C}_2 (2x )^3 (3y )^2 + ^{5}{}{C}_3 (2x )^2 (3y )^3 + ^{5}{}{C}_4 (2x )^1 (3y )^4 +^{5}{}{C}_5 (2x )^0 (3y )^5\]

\[= 32 x^5 + 5 \times 16 x^4 \times 3y + 10 \times 8 x^3 \times 9 y^2 + 10 \times 4 x^2 \times 27 y^3 + 5 \times 2x \times 81 y^4 + 243 y^5 \]
\[ = 32 x^5 + 240 x^4 y + 720 x^3 y^2 + 1080 x^2 y^3 + 810x y^4 + 243 y^5 \]

 

 


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