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Find ( X + 1 ) 6 + ( X − 1 ) 6 . Hence, Or Otherwise Evaluate ( √ 2 + 1 ) 6 + √ 2 − 1 6 . - Mathematics

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प्रश्न

Find \[\left( x + 1 \right)^6 + \left( x - 1 \right)^6\] . Hence, or otherwise evaluate \[\left( \sqrt{2} + 1 \right)^6 + \sqrt{2} - 1^6\] .

 

 

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उत्तर

The expression  \[\left( x + 1 \right)^6 + \left( x - 1 \right)^6\]  can be written as \[(x + 1 )^6 + (x - 1 )^6 \]
\[ = 2[ ^{6}{}{C}_0 x^6 +^{6}{}{C}_2 x^4 + ^{6}{}{C}_4 x^2 + ^{6}{}{C}_6 x^0 ]\]
\[ = 2[ x^6 + 15 x^4 + 15 x^2 + 1]\]

By taking \[x = \sqrt{2}\] , we get:

\[(\sqrt{2} + 1 )^6 + (\sqrt{2} - 1 )^6 = 2[(\sqrt{2} )^6 + 15(\sqrt{2} )^4 + 15(\sqrt{2} )^2 + 1]\]

\[ = 2[8 + 15 \times 4 + 15 \times 2 + 1]\]
\[ = 2 \times (8 + 60 + 30 + 1)\]
\[ = 198\]
  
 
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Introduction of Binomial Theorem
  क्या इस प्रश्न या उत्तर में कोई त्रुटि है?
अध्याय 18: Binomial Theorem - Exercise 18.1 [पृष्ठ ११]

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आरडी शर्मा Mathematics [English] Class 11
अध्याय 18 Binomial Theorem
Exercise 18.1 | Q 4 | पृष्ठ ११

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