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प्रश्न
Two friends leave Delhi for Chandigarh in their cars. A starts at 5 am and moves with a constant speed of 30 km/h, whereas B starts at 6 am and moves with a constant speed of 40 kmh-1. Plot the distance-time graph for their motion and find at what time the two friends will meet and at what distance from Delhi.
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उत्तर
So we can see that the two friends wiil meet at 9 a.m ant till then they cover a distance of u x t = u' xt' = 30 x4 = 40 x 3 =120 km So they are 120 km away from Delhi when they meet at 9 a.m.
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संबंधित प्रश्न
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Show the shape of the distance – time graph for the motion in the following cases.
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Two students were asked to plot a distance-time graph for the motion described by Table A and Table B.
| Table A |
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| Distance moved (m) | 0 | 10 | 20 | 30 | 40 | 50 |
| Time (minutes) | 0 | 2 | 4 | 6 | 8 | 10 |
| Table B |
||||||
| Distance moved (m) | 0 | 5 | 10 | 15 | 20 | 25 |
| Time (minutes) | 0 | 1 | 2 | 3 | 4 | 5 |
The graph given in figure is true for
If we denote speed by S, distance by D and time by T, the relationship between these quantities is ______.
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| Distance (m) | 0 | 4 | ? | 12 | ? | 20 |
| Time (s) | 0 | 2 | 4 | ? | 8 | 10 |
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