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Two circular loops, one of small radius r and the other of larger radius R, such that R >> r, are placed coaxially with centres coinciding. Obtain the mutual inductance of the arrangement. - Physics

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प्रश्न

Two circular loops, one of small radius r and the other of larger radius R, such that R >> r, are placed coaxially with centres coinciding. Obtain the mutual inductance of the arrangement.

प्रमेय
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उत्तर

Let a current IP flow through the circular loop of radius R. The magnetic induction at the centre of the loop is

BP = `(mu_0I_P)/(2R)`

As, r << R, the magnetic induction BP may be considered to be constant over the entire cross-sectional area of the inner loop of radius r. Hence magnetic flux linked with the smaller loop will be

`Φ_S = B_PA_S = (mu_0I_P)/(2R)pir^2`

Also, ΦS = MIP

∴ M = `Phi_S/I_P = (mu_0pir^2)/(2R)`

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