Question

Two circular loops, one of small radius r and the other of larger radius R, such that R >> r, are placed coaxially with centres coinciding. Obtain the mutual inductance of the arrangement.

Answer 1

Let a current I_P flow through the circular loop of radius R. The magnetic induction at the centre of the loop is

B_P = `(mu_0I_P)/(2R)`

As, r << R, the magnetic induction B_P may be considered to be constant over the entire cross-sectional area of the inner loop of radius r. Hence magnetic flux linked with the smaller loop will be

`Φ_S = B_PA_S = (mu_0I_P)/(2R)pir^2`

Also, Φ_S = MI_P

∴ M = `Phi_S/I_P = (mu_0pir^2)/(2R)`