हिंदी

Two long straight parallel current-carrying conductors are kept ‘a’ distant apart in the air. The direction of current in both the conductors is the same. Find the magnitude of force per unit length - Physics

Advertisements
Advertisements

प्रश्न

Two long straight parallel current-carrying conductors are kept ‘a’ distant apart in the air. The direction of current in both the conductors is the same. Find the magnitude of force per unit length and the direction of the force between them. Hence define one ampere.

योग
Advertisements

उत्तर

The magnetic induction B1 set up by the current I1 flowing in the first conductor at a point somewhere in the middle of the second conductor is

`B_1 = (mu_0I_1)/(2pia)`  ...(1)

The magnetic force acting on the portion P2Q2 of length ℓ2 of the second conductor is

F2 = l22 B1 sin 90°   ...(2)

From equation (1) and (2),

F2 = `(mu_0I_1I_2ℓ_2)/(2pia)`, towards first conductor

`F_2/ℓ_2 = (mu_0I_1I_2)/(2pia)`   ...(3)

The magnetic induction B2 set up by the current I2 flowing in the second conductor at a point somewhere in the middle of the first conductor is

`B_2 = (mu_0I_2)/(2pia)`   ...(4)

The magnetic force acting on the portion P1Q1 of length ℓ1 of the first conductor is

F1 = I11B2 sin 90°    ...(5)

From equation (3) and (5)

`F_1 = (mu_0I_1I_2ℓ_1)/(2pia)`, towards second conductor

`F_1/ℓ_1 = (mu_0I_1I_2)/(2pia)`  ...(6)

The standard definition of 1A

If I1 = I2 = 1A

1 = ℓ2 = 1m

a = 1m in V/A then `F_1/ℓ_1 = F_2/ℓ_2 = (mu_0 xx 1 xx 1)/(2pi xx 1) = 2 xx 10^-7` N/m

∴ One ampere is that electric current which when flows in each one of the two infinitely long straight parallel conductors placed 1m apart in vacuum causes each one of them to experience a force of 2 × 10-7 N/m.

shaalaa.com
  क्या इस प्रश्न या उत्तर में कोई त्रुटि है?
2023-2024 (March) Board Sample Paper

वीडियो ट्यूटोरियलVIEW ALL [1]

संबंधित प्रश्न

The figure shows three infinitely long straight parallel current carrying conductors. Find the

  1. magnitude and direction of the net magnetic field at point A lying on conductor 1,
  2. magnetic force on conductor 2.


Derive the expression for force per unit length between two long straight parallel current carrying conductors. Hence define one ampere.


A charged particle goes undeflected in a region containing an electric and a magnetic field. It is possible that
(a) `vecE" || "vecB , vecv" || " vec E `
(b) `vecE  "is not parallel"  vecB`
(c) `vecv " || " vecB  but  vecv  "is not parallel"`
(d) `vecE" || " vecB  but   vecv "is not parallel"`


Two long, straight wires, each carrying a current of 5 A, are placed along the x- and y-axis respectively. The currents point along the positive directions of the axes. Find the magnetic fields at the points (a) (1 m, 1 m), (b) (−1 m, 1 m), (c) (−1 m, −1 m) and (d) (1 m, −1 m). 


A long, straight wire carries a current i. Let B1 be the magnetic field at a point P at a distance d from the wire. Consider a section of length l of this wire such that the point P lies on a perpendicular bisector of the section B2 be the magnetic field at this point due to this second only. Find the value of d/l so that B2 differs from B1 by 1%.    


Answer the following question.
Two infinitely long straight wire A1 and A2 carrying currents I and 2I flowing in the same direction are kept' distance apart. Where should a third straight wire A3 carrying current 1.5 I be placed between A1 and A2 so that it experiences no net force due to A1 and A2? Does the net force acting on A3 depend on the current flowing through it?


If a current I is flowing in a straight wire parallel to x-axis and magnetic field is there in the y-axis then, ______.


Equal currents are passing through two very long and straight parallel wires in the same direction. They will ______


Do magnetic forces obey Newton’s third law. Verify for two current elements dl1 = dlî located at the origin and dl2 = dlĵ located at (0, R, 0). Both carry current I.


Beams of electrons and protons move parallel to each other in the same direction. They ______.


Share
Notifications

Englishहिंदीमराठी


      Forgot password?
Use app×