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The molecules of a given mass of a gas have root mean square speeds of 100 ms−1 at 27°C and 1.00 atmospheric pressure. - Physics

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प्रश्न

The molecules of a given mass of a gas have root mean square speeds of 100 ms−1 at 27°C and 1.00 atmospheric pressure. What will be the root mean square speeds of the molecules of the gas at 127°C and 2.0 atmospheric pressure?

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उत्तर

We know that for a given mass of a gas

`V_(rms) = sqrt((3RT)/M)`

Where R is gas constant

T is the temperature in Kelvin

M is the molar mass of the gas

Clearly, `V_(rms) ∝ sqrt(T)`

As R and M are constants,

`(V_(rms))_1/(V_(rms))_2 = sqrt(T_1/T_2)`

Given, `(V_(rms))_1` = 100 m/s

T1 = 27°C = 27 + 273 = 300 K

T2 = 127°C = 127 + 273 = 400 K

∴ From equation (i)

`100/((V_(rms))_2) = sqrt(300/400) = sqrt(3)/2`

⇒ `(V_(rms))_2 = (2 xx 100)/sqrt(3) = 200/sqrt(3)` m/s

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अध्याय 13: Kinetic Theory - Exercises [पृष्ठ ९४]

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एनसीईआरटी एक्झांप्लर Physics [English] Class 11
अध्याय 13 Kinetic Theory
Exercises | Q 13.16 | पृष्ठ ९४

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