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प्रश्न
The figure shows a circuit. When the circuit is switched on, the ammeter reads 0.5 A.
(i) Calculate the value of the unknown resistor R.
(ii) Calculate the charge passing through the 3 Ω resistor in 120 s.
(iii) Calculate the power dissipated in the 3 Ω resistor.
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उत्तर
(i) We know, V = IR'
⇒ 6 = 0.5 × R'
⇒ R' = 12 Ohm
∵ R' = 3 + R
⇒ 12 = 3 + R
⇒ R = 9 Ohm
(ii) Charge, q = i t
⇒ q = 0.5 × 120 = 60 Coulomb
(iii) Power dissipation, p = i2R
p = 0.52 × 3 = 0.75 Watt
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संबंधित प्रश्न
The values of current (I) flowing through a given resistor of resistance (R), for the corresponding values of potential difference (V) across the resistor are as given below:
| V (volts) | 0.5 | 1.0 | 1.5 | 2.0 | 2.5 | 3.0 | 4.0 | 5.0 |
| I (amperes) | 0.1 | 0.2 | 0.3 | 0.4 | 0.5 | 0.6 | 0.8 | 1.0 |
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