Advertisements
Advertisements
प्रश्न
Three resistors are connected to a 6 V battery as shown in the figure given below:

Calculate:
(i) the equivalent resistance of the circuit.
(ii) total current in the circuit.
(iii) potential difference across the 7.2 Ω resistor.
Advertisements
उत्तर
(i) `1/"R"_1 = 1/8 + 1/12`
`= (3 + 2)/24 = 5/24`
R1 = 4.8 ohm.
Total Resistance = 4.8 + 7.2 = 12 ohm
(ii) V = IR
6 = I × 12
I = 0.5 Amp.
(iii) V = IR
= 0.5 × 7.2
= 3.6 Volt.
संबंधित प्रश्न
You have three resistors of values 2Ω, 3Ω and 5Ω. How will you join them so that the total resistance is more than 7Ω?
1) Draw a diagram for the arrangement
2) Calculate the equivalent resistance.
What is the SI unit of potential difference?
The p.d. across a lamp is 12 V. How many joules of electrical energy are changed into heat and light when: a current of 2 A flows through it for 10 s?
A resistance of 20 ohms has a current of 2 amperes flowing in it. What potential difference is there between its ends?
What is Ohm's law? Explain how it is used to define the unit of resistance.
For the circuit shown in the diagram below:
What is the value of:
(i) current through 6 Ω resistor?
(ii) potential difference across 12 Ω resistor?
An electric bulb draws 0.5 A current at 3.0 V. Calculate the resistance of the filament of the bulb.
If P and V are the power and potential of device, the power consumed with a supply potential V1 is:
How will you conclude that the same potential difference (voltage) exists across three resistors connected in a parallel arrangement to a battery?
Find the potential difference required to flow a current of 300 mA in a wire of resistance 20 Ω.
