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The Complex Number Z Which Satisfies the Condition ∣ ∣ ∣ I + Z I − Z ∣ ∣ ∣ = 1 Lies on

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प्रश्न

The complex number z which satisfies the condition \[\left| \frac{i + z}{i - z} \right| = 1\] lies on

विकल्प

  • circle x2 + y2 = 1

  • the x−axis

  • the y−axis

  • the line x + y = 1

MCQ
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उत्तर

\[\left| \frac{i + z}{i - z} \right| = 1\]

\[ \Rightarrow \left| \frac{i + z}{i - z} \right|^2 = 1^2 \]

\[ \Rightarrow \left( \frac{i + z}{i - z} \right) \bar{\left( \frac{i + z}{i - z} \right)} = 1\]

\[ \Rightarrow \left( \frac{i + z}{i - z} \right)\left( \frac{- i + \bar{z}}{- i - \bar{z}} \right) = 1\]

\[ \Rightarrow \left( \frac{- i^2 - zi + \bar{z}i + z \bar{z}}{- i^2 + zi - \bar{z}i + z \bar{z}} \right) = 1\]

\[ \Rightarrow - i^2 - zi + \bar{z}i + z \bar{z} = - i^2 + zi - \bar{z}i + z \bar{z}\]

\[ \Rightarrow - zi + \bar{z}i = zi - \bar{z}i\]

\[ \Rightarrow \bar{z}i + \bar{z}i = zi + zi\]

\[ \Rightarrow 2 \bar{z}i = 2zi\]

\[ \Rightarrow \bar{z} = z\]

\[ \Rightarrow \text { z is purely real }\]

Hence, the correct option is (b).

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  क्या इस प्रश्न या उत्तर में कोई त्रुटि है?
अध्याय 13: Complex Numbers - Exercise 13.6 [पृष्ठ ६६]

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आर.डी. शर्मा Mathematics [English] Class 11
अध्याय 13 Complex Numbers
Exercise 13.6 | Q 40 | पृष्ठ ६६

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