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प्रश्न
Structure of a disaccharide formed by glucose and fructose is given below. Identify anomeric carbon atoms in monosaccharide units.

विकल्प
‘a’ carbon of glucose and ‘a’ carbon of fructose.
‘a’ carbon of glucose and ‘e’ carbon of fructose.
‘a’ carbon of glucose and ‘b’ carbon of fructose.
‘f’ carbon of glucose and ‘f ’ carbon of fructose.
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उत्तर
‘a’ carbon of glucose and ‘b’ carbon of fructose.
Explanation:
Carbon adjacent to oxygen atom in the cyclic structure of glucose or fructose is known as anomeric carbon. As shown in the structure above ‘a’ and ‘b’ are present at adjacent to oxygen atom. Both carbons differ in configurations of the hydroxyl group.
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संबंधित प्रश्न
Write two main functions of carbohydrates in plants.
What are reducing sugars?
Classify the following into monosaccharides and disaccharides.
Ribose, 2-deoxyribose, maltose, galactose, fructose and lactose
The number of primary and secondary hydroxyl groups in ribose are -
(a) 1, 3
(b) 2, 3
(c) 3, 1
(d) 3, 2
The following molecule is called as:
\[\begin{array}{cc}
\ce{CHO}\phantom{..}\\
|\phantom{......}\\
\ce{(CHOH)4}\\
|\phantom{......}\\
\ce{CH2OH}
\end{array}\]
Glycosidic linkage is found between ____________.
Which of the following gives a positive Fehling solution test?
Monosaccharides usually contains ____________ carbon atoms.
Reducing sugars reduce ____________.
Which of the following reagent cannot distinguish between glucose and fructose?
Three cyclic structures of monosaccharides are given below which of these are anomers.
| (I) | ![]() |
| (II) | ![]() |
| (III) | ![]() |
Name the sugar present in milk. How many monosaccharide units are present in it? What are such oligosaccharides called?
Monosaccharides contain carbonyl group hence are classified, as aldose or ketose. The number of carbon atoms present in the monosaccharide molecule are also considered for classification. In which class of monosaccharide will you place fructose?
What are glycosidic linkages? In which type of biomolecules are they present?
Assertion: Deoxyribose, \[\ce{C5H10O4}\] is not a carbohydrate.
Reason: Carbohydrates are hydrates of carbon so compounds which follow \[\ce{C_x(H2O)_y}\] formula are carbohydrates.
Account for the following:
Glucose is a reducing sugar



