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प्रश्न
Glucose or sucrose are soluble in water but cyclohexane or benzene (simple six membered ring compounds) are insoluble in water. Explain.
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उत्तर
A glucose molecule contains five −OH groups, while a sucrose molecule contains eight −OH groups. Thus, glucose and sucrose undergo extensive H-bonding with water. Hence, these are soluble in water. But cyclohexane and benzene do not contain −OH groups. Hence, they cannot undergo H-bonding with water and as a result, are insoluble in water.
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संबंधित प्रश्न
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| (I) |  |
| (II) |  |
| (III) |  |
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