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कर्नाटक बोर्ड पी.यू.सी.पीयूसी विज्ञान 2nd PUC Class 12

What are the hydrolysis products of sucrose?

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प्रश्न

What are the hydrolysis products of sucrose?

अति संक्षिप्त उत्तर
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उत्तर

Sucrose on hydrolysis gives one unit of glucose and one unit of fructose.

\[\ce{\underset{Sucrose}{C12H22O11} + H2O ->[Invertase][or H3O+] \underset{Glucose}{C6H12O6} + \underset{Fructose}{C6H12O6}}\]

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अध्याय 10: Biomolecules - Exercises [पृष्ठ ३०२]

संबंधित प्रश्न

Glucose or sucrose are soluble in water but cyclohexane or benzene (simple six membered ring compounds) are insoluble in water. Explain.


Write two main functions of carbohydrates in plants.


Classify the following into monosaccharides and disaccharides.

Ribose, 2-deoxyribose, maltose, galactose, fructose and lactose


The following molecule is called as:

\[\begin{array}{cc}
\ce{CHO}\phantom{..}\\
|\phantom{......}\\
\ce{(CHOH)4}\\
|\phantom{......}\\
\ce{CH2OH}
\end{array}\]


Which of the following gives a positive Fehling solution test?


Which of the following monosaccharide is pentose?


Monosaccharides usually contains ____________ carbon atoms.


A carbohydrate that cannot be hydrolysed into simpler units is called ____________.


Reducing sugars reduce ____________.


Glucose can’t be classified as ____________.


Which of the following reagent cannot distinguish between glucose and fructose?


Three cyclic structures of monosaccharides are given below which of these are anomers.

(I)
(II)
(III)

Name the sugar present in milk. How many monosaccharide units are present in it? What are such oligosaccharides called?


Name the linkage connecting monosaccharide units in polysaccharides.


Monosaccharides contain carbonyl group hence are classified, as aldose or ketose. The number of carbon atoms present in the monosaccharide molecule are also considered for classification. In which class of monosaccharide will you place fructose?


Which monosaccharide units are present in starch, cellulose and glucose and which linkages link these units?


Assertion: Deoxyribose, \[\ce{C5H10O4}\] is not a carbohydrate.

Reason: Carbohydrates are hydrates of carbon so compounds which follow \[\ce{C_x(H2O)_y}\] formula are carbohydrates.


Account for the following:

Glucose is a reducing sugar


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