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प्रश्न
sinx2 + sin2x + sin2(x2)
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उत्तर
Let sinx2 + sin2x + sin2(x2)
∴ `"dy"/"dx" = "d"/"dx" sin(x^2) + "d"/"dx" (sinx)^2 + "d"/"dx" (sin x^2)^2`
= `cos(x^2) "d"/"dx" (x^2) + 2 sinx * "d"/"dx" (sin x) + 2 sinx^2 "d"/"dx" (sin x^2)`
= `2x cosx^2 + 2 sin x cos x + 2sinx^2 cosx^2 "d"/"dx" x^2`
= `2x cosx^2 + 2 sin x cos x + 2 sin x^2 cos x^2 xx 2x`
= 2x cos(x2) + sin 2x + 2x sin 2(x2)
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