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If y1-x2+x1-y2 = 1, then prove that dydx=-1-y21-x2

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प्रश्न

If `ysqrt(1 - x^2) + xsqrt(1 - y^2)` = 1, then prove that `(dy)/(dx) = - sqrt((1 - y^2)/(1 - x^2))`

योग
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उत्तर

`ysqrt(1 - x^2) + xsqrt(1 - y^2)` = 1

Let sin–1x = A and sin–1y = B.

Then x = sinA and y = sinB

`ysqrt(1 - x^2) + xsqrt(1 - y^2)` = 1

⇒ sinBcosA + sinAcosB = 1

⇒ sin(A + B) = 1

⇒ A + B = sin–11 = `pi/2`

⇒ sin–1x + sin–1y = `pi/2`

Differentiating w.r.to x, we obtain `(dy)/(dx) = - sqrt((1 - y^2)/(1 - x^2))`

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